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Simplify hexfloat rounding and test long double ties
Avoids shifting by zero, which is undefined for the fallback uint128. The float tie test duplicated the double one; floats format as doubles.
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@ -3366,18 +3366,10 @@ FMT_CONSTEXPR20 void format_hexfloat(Float value, format_specs specs,
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int print_xdigits = num_xdigits - 1;
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if (specs.precision >= 0 && print_xdigits > specs.precision) {
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const int shift = ((print_xdigits - specs.precision - 1) * 4);
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const auto mask = carrier_uint(0xF) << shift;
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const auto v = static_cast<uint32_t>((f.f & mask) >> shift);
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const int shift = (print_xdigits - specs.precision) * 4;
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const auto inc = carrier_uint(1) << shift;
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// Round half to even like printf.
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const bool odd = ((f.f >> (shift + 4)) & 1) != 0;
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const bool rest_is_zero = (f.f & ((carrier_uint(1) << shift) - 1)) == 0;
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if (v > 8 || (v == 8 && (odd || !rest_is_zero))) {
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const auto inc = carrier_uint(1) << (shift + 4);
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f.f += inc;
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f.f &= ~(inc - 1);
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}
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f.f += (inc >> 1) - 1 + ((f.f >> shift) & 1);
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// Check long double overflow.
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if (!has_implicit_bit<Float>()) {
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@ -1756,7 +1756,8 @@ TEST(format_test, format_double) {
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EXPECT_EQ(fmt::format("{:.1a}", 1.03125), "0x1.0p+0");
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EXPECT_EQ(fmt::format("{:.1a}", 1.09375), "0x1.2p+0");
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EXPECT_EQ(fmt::format("{:.1a}", 1.0322265625), "0x1.1p+0");
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EXPECT_EQ(fmt::format("{:.1A}", 1.03125f), "0X1.0P+0");
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if (std::numeric_limits<long double>::digits == 64)
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EXPECT_EQ(fmt::format("{:.0a}", 1.0625l), "0x8p-3");
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EXPECT_EQ(fmt::format("{:a}", -42.0), "-0x1.5p+5");
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EXPECT_EQ(fmt::format("{:A}", -42.0), "-0X1.5P+5");
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